Odpowiedź:
I sposób
log72 = log(3
2
· 2
3
) = log3
2
+ log2
3
=
= 2log3 + 3log2 = 2a + 3b
II sposób
log 72 = log(2 · 36) = log2 + log6
2
=
= log2 + 2log6 = log2 + 2(log2 + log3) =
= 3log2 + 2log3 = 3b + 2a